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FirstMissingPositive.java
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package arrays.hard;
import java.util.Arrays;
/***
* Problem 41 in Leetcode: https://leetcode.com/problems/first-missing-positive/
*
* Given an unsorted integer array nums, return the smallest missing positive integer.
* You must implement an algorithm that runs in O(n) time and uses constant extra space.
*
* Example 1:
* Input: nums = [1,2,0]
* Output: 3
*
* Example 2:
* Input: nums = [3,4,-1,1]
* Output: 2
*
* Example 3:
* Input: nums = [7,8,9,11,12]
* Output: 1
*/
public class FirstMissingPositive {
public static void main(String[] args) {
// int[] nums = {7, 8, 9, 11, 12};
int[] nums = {1, 2, 3, 4, 5};
System.out.println("Brute Force: " + firstMissingPositiveBruteForce(nums));
System.out.println("Sorting: " + firstMissingPositiveSorting(nums));
System.out.println("Count Array: " + firstMissingPositiveCountArray(nums));
System.out.println("Swapping: " + firstMissingPositiveSwapping(nums));
System.out.println("Negation: " + firstMissingPositiveNegation(nums));
}
private static int firstMissingPositiveBruteForce(int[] nums) {
int n = nums.length;
for (int i = 1; i <= n; i++) {
boolean found = false;
for (int num : nums) {
if (num == i) {
found = true;
break;
}
}
if (!found) {
return i;
}
}
return n + 1;
}
private static int firstMissingPositiveSorting(int[] nums) {
Arrays.sort(nums);
int missingNumber = 1;
for (int num : nums) {
if (num == missingNumber) {
missingNumber++;
}
}
return missingNumber;
}
private static int firstMissingPositiveCountArray(int[] nums) {
int n = (int) 1e5 + 2;
int[] count = new int[n];
for (int num : nums) {
if (num > 0) {
count[num] = 1;
}
}
for (int i = 1; i <= nums.length; i++) {
if (count[i] == 0) {
return i;
}
}
return nums.length + 1;
}
private static int firstMissingPositiveSwapping(int[] nums) {
int n = nums.length;
for (int i = 0; i < n; i++) {
int position = nums[i] - 1;
while (((position >= 0) && (position < n)) && (nums[i] != nums[position])) {
int temp = nums[i];
nums[i] = nums[position];
nums[position] = temp;
position = nums[i] - 1;
}
}
for (int i = 0; i < n; i++) {
if (i != (nums[i] - 1)) {
return i + 1;
}
}
return n + 1;
}
private static int firstMissingPositiveNegation(int[] nums) {
int n = nums.length;
for (int i = 0; i < n; i++) {
if (nums[i] <= 0) {
nums[i] = 0;
}
}
for (int num : nums) {
num = Math.abs(num);
int index = num - 1;
if ((index >= 0) && (index < n)) {
if (nums[index] == 0) {
nums[index] = -(n + 1);
} else if (nums[index] > 0) {
nums[index] = -nums[index];
}
}
}
for (int i = 1; i <= n; i++) {
int index = i - 1;
if (nums[index] >= 0) {
return i;
}
}
return n + 1;
}
}