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[remove datanode] Load balancing for removing datanode #15022

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@HxpSerein HxpSerein commented Mar 5, 2025

Description

Add region migration dest datanode selection algorithm for load balancing during removing datanode.

Please see https://apache-iotdb-project.feishu.cn/docx/G5aPdZJ4QozqmkxO9dsc7sEsnTe for detail design.

fakeToRealIdMap.keySet().stream()
.filter(fakeId -> !remainDataNodesFakeId.contains(fakeId))
.collect(Collectors.toSet());
return availableDataNodeMap.get(alternativeDataNodes.stream().findAny().orElse(null));
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What's the meaning of get(null) ?

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removed

allocatedRegionGroups.remove(replicaSet);
List<TDataNodeLocation> dataNodeLocations = replicaSet.getDataNodeLocations();
dataNodeLocations.remove(replicaSetRemoved.get(replicaSet.getRegionId()));
replicaSet.setDataNodeLocations(dataNodeLocations);
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do we need to do this as you just remove it from replicaSet.getDataNodeLocations()

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Now allocatedReplicaSets is HashSet, and the hash value of ReplicaSets will change. Removing, updating, and adding them is a safer approach

for (TRegionReplicaSet replicaSet : replicaSets) {
replicaSetRemoved.put(replicaSet.getRegionId(), dataNodeLocation);
}
migratedReplicas.addAll(replicaSets);
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It looks like it might repeat when we support removing multiple nodes in the future, right? Maybe we should use a set

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done.

.getClusterSchemaManager()
.getReplicationFactor(database, consensusGroupType);
} catch (DatabaseNotExistsException e) {
LOGGER.error(
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use warn

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done.

allocatedRegionGroups.remove(remainReplicaSet);
List<TDataNodeLocation> dataNodeLocations = remainReplicaSet.getDataNodeLocations();
dataNodeLocations.add(selectedDestDataNode.getLocation());
remainReplicaSet.setDataNodeLocations(dataNodeLocations);
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same as above

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@HxpSerein HxpSerein Mar 7, 2025

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To ensure the correctness and readability of the code, it is recommended to retain the remove and add operations.

return regionMigrationPlans;
}

public List<RegionMigrationPlan> selectMigrationPlans(
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maybe you can use gpt to refactor and improve the code here

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done.

break;
}
alternativeReplica[replicationFactor - 1] = dataNodeEntry.dataNodeId;
Pair<Integer, Integer> currentValue = valuation(alternativeReplica);
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So should we consider the number of regions first instead of divergence?

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@HxpSerein HxpSerein Mar 7, 2025

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Such is the case. Only dataNodeEntries that meet the criteria of dataNodeEntry.freeDiskSpace == minFreeDiskSpace will be considered.

allocateResult.remove(remainReplicaSet);
List<TDataNodeLocation> dataNodeLocations = remainReplicaSet.getDataNodeLocations();
dataNodeLocations.add(selectedNode.getLocation());
remainReplicaSet.setDataNodeLocations(dataNodeLocations);
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duplicated?

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removed

List<TDataNodeLocation> dataNodeLocations = replicaSet.getDataNodeLocations();
allocateResult.remove(replicaSet);
dataNodeLocations.remove(REMOVE_DATANODE_LOCATION);
replicaSet.setDataNodeLocations(dataNodeLocations);
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duplicated?

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removed

selectedNodeIds.add(selectedNode.getLocation().getDataNodeId());
}

Assert.assertEquals(TEST_DATA_NODE_NUM - 1, selectedNodeIds.size());
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Should we calculate how many new regions are added to each node, whether they are balanced, and so on? Otherwise this is a little bit broad at the moment?

maybe something like this
image

image

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added.

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2 participants