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[extractor/golang] Generate valid golang purls #501

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schischi
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According to the purl spec, the golang type is using both name and namespace.

Scalibr is only populating the name, resulting in a single percent-encoded string instead of a namespace with multiple segments and a name: Example:

  • Purl-spec: pkg:golang/github.com/google/osv-scalibr
  • Scalibr: pkg:golang/github.com%2Fgoogle%2Fosv-scalibr

See: https://github.com/package-url/purl-spec/blob/main/PURL-TYPES.rst#golang

According to the purl spec, the golang type is using both name and namespace.

Scalibr is only populating the name, resulting in a single percent-encoded
string instead of a namespace with multiple segments and a name:
Example:
 - Purl-spec: pkg:golang/github.com/google/osv-scalibr
 - Scalibr:   pkg:golang/github.com%2Fgoogle%2Fosv-scalibr

See: https://github.com/package-url/purl-spec/blob/main/PURL-TYPES.rst#golang
@erikvarga
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Thanks for catching this!

@@ -140,10 +140,12 @@ func (e Extractor) Extract(ctx context.Context, input *filesystem.ScanInput) ([]

// ToPURL converts an inventory created by this extractor into a PURL.
func (e Extractor) ToPURL(i *extractor.Inventory) *purl.PackageURL {
nameParts := strings.Split(i.Name, "/")
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Since we're doing this in two places can you move the ToPURL logic into a separate library inside language/golang, similar to https://github.com/google/osv-scalibr/blob/main/extractor/filesystem/language/python/internal/pypipurl/pythonpurl.go?

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2 participants